TCS Exam 24th August 2022 2pm Slot Answers Live

TCS Exam 24th August 2022 2pm Slot Answers Live

Aptitude :-

1) 10

2) 0.4

3) 196

4) 0.18

5) 60

6) 34

7) 195

8) 716

9) 6.44

10) Rs. 28200

11) 10ltr

12) 15.55

13) 42

14) 6

15) 1640km

16) Rs 945

17) 264

18) 40000 or 50000

19) 6.667

20) 28

Aptitude Completed

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Verbal :-

1) Sustained stress because of the mother-in-law

2) Then the cricket field was

3) that i am always

4) Engaged,crown,completely,pioneer

5) 1-(B),2(D),3(c),4(A)

6) Mamta..

7) Laboured under, worried the teaspoons..

8) Majar Bombshell

OR

8) Major blow, weighing on demand,grapple with, spur capital flows

9) 2143

10) ABCED

11) CBDAE

12) RS

13) Something that changes over,in what is produced

14) has been made in reducing, remains a leading killer

15) Indigenous

16) amateur

17) C

18)PR

19) vile decided to postpone his trip

20) Vile had not been able to stick to original plans

21) RST

22) Ancient mathematician euclide geometry theories.

23) By visualizing space in geometrical dilite

24) the hypothesis..

25) it has been man's abiding interest..

Verbal Completed

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Reasoning :-

1) ZADE

2) B,C & E

3)

4) 

5) Data

6) All statements

7) Father's father

8) k%

9) Lalit

10) Her (A)

11) The Case

12) Only

13) Both

14)
15) A &D

18) IFM

19) M

20) k

Compled

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Advanced Quantitative :-

1) 0.11

2)x-y=1

3) Xsquare -2x+16=0

4) P&Q

5)0.66

6.15

7) 14

8)  system engineer

9) 1246

10) 236

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Advanced Reasoning :-

1- ZADE

2- b,c and e

5- data in statement 1 is sufficient

6- all statements...

7- Father's Father

8- K%L$M

9- Lalit

10- other applications not to be accepted

11- Director

12- only assumption 1 is implicit

13- Both...

14- A and B

15- fig.473

18- IFM

19- M

20 -K

--------------------------------------------------------------------

Coding :-

1Ques

Answer:- C lang code 

#include <stdio.h>

int main() {

  int n, i, flag = 0;
  printf("Enter a positive integer: ");
  scanf("%d", &n);

 
  if (n == 0 || n == 1)
    flag = 1;

  for (i = 2; i <= n / 2; ++i) {

  
    if (n % i == 0) {
      flag = 1;
      break;
    }

  if (flag == 0)
    printf("%d .", n);
  else
    printf("%d ", n);

  return 0;
}

Two Parallel Roads Python Code :-

C language code :-

#include<stdio.h>
int main()
{
    int n,m;
    scanf("%d%d",&n,&m);
    int a[n],b[m];
    int temp[m+n];
    for(int i=0;i<n;i++)
    {
        scanf("%d",&a[i]);
    }
    for(int i=0;i<m;i++)
    {
        scanf("%d",&b[i]);
    }
    int x=0;
    for(int i=0;i<n;i++)
    {
        temp[x++]=a[i];
    }
    for(int i=0;i<m;i++)
    {
        temp[x++]=b[i];
    }
    for(int i=0;i<x;i++)
    {
        for(int j=i+1;j<x;j++)
        {
             if(temp[i]>temp[j])
             {
                 int t=temp[i];
                 temp[i]=temp[j];
                 temp[j]=t;
             }
        }
    }
    int count=0;
    for(int i=0;i<x;i++)
    {
        if(temp[i]==temp[i+1])
        {
            for(int j=i+1;j<x-1;j++)
            {
                temp[j]=temp[j+1];
                count=1;
            }
            x--;
        }
    }
    if(count==1)
    {
        x++;
    }

    if(x%2==0)
    {
        int mid=x/2;
        int mid1=x/2-1;
        int up=temp[mid]+temp[mid1];
        float result=up/2.0;
        printf("%.2f",result);
    }
    else
    {
        printf("%d",temp[x/2]);
    }
    return 0;
}

Two parallel working code:-

Storeroom code in c++ :-

#include <iostream>

#include<bits/stdc++.h>

using namespace std;

int main() {

    int n1,n2,i,j,c;

    cin>>n1>>n2;

    int a[n1],b[n2];

     set<int> s;

    for(i=0;i<n1;i++)

    {

        cin>>a[i];

        s.insert(a[i]);

    }

    

    for(i=0;i<n2;i++)

    {

        cin>>b[i];

        s.insert(b[i]);

    }

    vector<int> v(s.begin(),s.end()); 

    c=s.size();

    if(c%2==1)

    { 

        c=c/2;

        cout<<v[c];

    }

    else

    {

        n1=c/2;

        n2=n1-1;

        float q=(v[n1]+v[n2])/2.0;

        cout<<q;

    }

    

    

return 0;

}

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